A nuclear decay is expressed as [AIPMT 2000] |
\[_{6}{{C}^{11}}\to {{\,}_{5}}{{B}^{11}}+\,{{\beta }^{+}}+X\] |
Then the unknown particle X is: |
A) neutron
B) antineutrino
C) proton
D) neutrino
Correct Answer: B
Solution :
Key Idea: In a nuclear reaction conservation of charge number and mass number must hold good. |
Let Z be the charge number and A the mass number of particle X, then conservation of charge number gives. |
\[6=5+1+Z\] |
\[\Rightarrow \] \[Z=0\] |
Conservation of mass number gives, |
\[11=11+0+A\] |
\[\Rightarrow \] \[A=0\] |
X is a particle of zero charge and zero mass. This particle may be neutrino or antineutrino. With positive \[\beta -\]particle, neutrino is emitted and with negative \[\beta -\]particle, antineutrino is emitted. |
Thus, in our case neutrino will be emitted. |
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