A) \[20\mu g\]
B) \[40\mu g\]
C) \[1\,\mu g\]
D) \[10\,\mu g\]
Correct Answer: B
Solution :
Let assume power \[P=1000\text{ }W\] |
Energy per hour \[=1000\times 3600\text{ }J\] |
Energy per fission \[=200\text{ }MeV\] |
\[=200\times 1.6\times {{10}^{-13}}J\] |
\[\therefore \] Number of fission per hour |
\[n=\frac{1000\times 3600}{200\times 1.6\times {{10}^{-13}}}\] |
Number of mole per hour \[=\frac{n}{N}\times 235\] |
\[\therefore \] Mass per hour \[=\frac{n}{N}\times 235\] |
\[=\frac{1000\times 3600\times 235}{200\times 1.6\times {{10}^{-13}}\times 6.02\times {{10}^{23}}}\] |
\[=43.9\times {{10}^{-6}}g\] |
This \[43.9\times {{10}^{-6}}g\] is nearest value of 40 micron so option [b] is correct. |
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