A) 2.4
B) 1.2
C) 4.8
D) 3.6
Correct Answer: C
Solution :
Nuclear radius \[r\propto {{A}^{1/3}},\] where A is mass number |
\[r={{r}_{0}}{{A}^{1/3}}\] |
\[r={{r}_{0}}{{(27)}^{1/3}}=3{{r}_{0}}\] |
\[{{r}_{0}}\frac{3.6}{3}=1.2\,fm\] |
For \[^{64}Cu\] |
\[r={{r}_{0}}{{A}^{1/3}}\] |
\[=1.2\,fm\,{{(64)}^{1/3}}\] |
\[=4.8\,fm\,\] |
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