A) \[_{n}^{m-6}Z\]
B) \[_{n}^{m-4}X\]
C) \[_{n-2}^{m-4}Y\]
D) \[_{n-4}^{m-6}Z\]
Correct Answer: B
Solution :
\[_{n}^{m}X{{\xrightarrow[{}]{\alpha }}_{n-2}}{{X}^{m-4}}{{\xrightarrow[{}]{2\beta }}_{n}}{{X}^{m-4}}\]
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