NEET Physics Photo Electric Effect, X- Rays & Matter Waves NEET PYQ-Photo Electric Effect,X-Rays

  • question_answer
    An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly): \[({{m}_{e}}=9\times {{10}^{31}}kg)\]                                                                                  [NEET 2019]

    A)  \[12.2\times {{10}^{14}}m\]   

    B)  12.2 nm

    C)  \[12.2\times {{10}^{13}}m\]   

    D)  

    Correct Answer: D

    Solution :

    [d]  \[\lambda =\frac{12.27}{\sqrt{V}}{\AA}=\frac{12.27}{\sqrt{10,000}}{\AA}\]
    \[=12.27\times {{10}^{2}}\text{ }{\AA}\]
    \[=12.27\times {{10}^{12}}m\]


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