A) Teflon \[{{[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]}^{0}}\]
B) Neoprene \[{{[Co(en)C{{l}_{2}}{{(N{{H}_{3}})}_{2}}]}^{+}}\]
C)
Terylene 
D) Nylon 66 \[{{[Co{{(en)}_{3}}]}^{3+}}\]
Correct Answer: B
Solution :
| [b] Teflon is a polymer of tetrafluoroethylene. |
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| [b] Neoprene is a polymer of chloroprene (2-chloro buta-1, 3-diene). |
  |
| [c] Terylene is a polymer of terepthalic acid and ethylene glycol. |
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| [d] Nylon-66 is a polymer of hexamethylene diamine and adipic acid, |
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