A) \[\frac{2A}{\mu }\]
B) \[\mu A\]
C) \[\frac{\mu A}{2}\]
D) \[\frac{A}{2\mu }\]
Correct Answer: B
Solution :
[b] Light ray emerges normally from another surface, hence, e(angle of emergence) = 0 |
\[{{r}_{2}}=0\] |
\[{{r}_{1}}+{{r}_{2}}=A\] |
\[\Rightarrow {{r}_{1}}=A\] |
Applying Snell's law on first surface |
\[1.sin\,i=\mu \,sin\,\,{{r}_{1}}\] |
\[\Rightarrow \sin i=\mu \sin \,A\] |
For small angles \[(sin\,\theta \approx \theta )\] |
hence \[i=\text{ }\mu A\] |
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