question_answer

What is the change in oxidation number of carbon in the following reaction?                           [NEET 2020] \[C{{H}_{4}}(g)+4C{{l}_{2}}(g)\to CC{{l}_{4}}(l)+4HCl(g)\]

A)  0 to + 4          

B)       - 4 to + 4

C)  0 to - 4 D)       + 4 to + 4 Correct Answer: B Solution : [b] \[C{{H}_{4}}\Rightarrow x+4\times 1=0\Rightarrow x=4\]

\[CC{{l}_{4}}\Rightarrow \text{ }x+4\times (1)=0\Rightarrow x=+4\]

\[\overset{-4}{\mathop{C{{H}_{4}}(g)+4C{{l}_{2}}(g)\to \overset{+4}{\mathop{CC{{l}_{4}}(l)+4HCl(g)}}\,}}\,\]

Change in oxidation state of carbon is from -4 to +4