A) + 3, + 5, + 4
B) + 5, + 3, + 4
C) + 5, + 4, + 3
D) + 3, + 4, + 5
Correct Answer: D
Solution :
| Key Idea Oxidation state of H is + 1 and that of O is - 2. |
| Let the oxidation state of P in the given compounds is x. |
| In \[{{\text{H}}_{\text{4}}}{{\text{P}}_{\text{2}}}{{\text{O}}_{\text{5}}}\text{,}\] |
| \[(+1)\times 4+2\times x=(-2)\times 5=0\] |
| \[4+2x-10=0\] |
| \[2x=6\] |
| \[x=+3\] |
| \[\therefore \] |
| In\[{{H}_{4}}{{P}_{2}}{{O}_{6}},\] |
| \[(+1)\times 4+2\times x+(-2)\times 6=0\] |
| \[4+2x-12=0\] |
| \[2x=8\] |
| \[x=+4\] |
| \[\therefore \] |
| In \[{{H}_{4}}{{P}_{2}}{{O}_{7}},\] |
| \[(+1)\times 4+2\times x+(-2)\times 7=0\] |
| \[4+2x-14=0\] |
| \[2x=10\] |
| \[x=+5\] |
| \[\therefore \] |
| Thus, the oxidation states of P in \[{{H}_{4}}{{P}_{2}}{{O}_{5}},\] \[{{H}_{4}}{{P}_{2}}{{O}_{6}}\]and \[{{H}_{4}}{{P}_{2}}{{O}_{7}}\] are + 3, + 4 and + 5 respectively. |
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