A) \[\frac{1}{2}\,M{{R}^{2}}\]
B) \[M{{R}^{2}}\]
C) \[\frac{7}{2}M{{R}^{2}}\]
D) \[\frac{3}{2}M{{R}^{2}}\]
Correct Answer: D
Solution :
Key Idea: We should use parallel axis theorem. |
Moment of inertia of disc passing through its centre of gravity and perpendicular to its plane is |
\[{{I}_{AB}}=\frac{1}{2}M{{R}^{2}}\] |
Using theorem of parallel axes, we have, |
\[{{I}_{CD}}={{I}_{AB}}+M{{R}^{2}}\] |
\[=\frac{1}{2}M{{R}^{2}}+M{{R}^{2}}\] |
\[=\frac{3}{2}M{{R}^{2}}\] |
Note: The role of moment of inertia in the study of rotational motion is analogous to that or mass in study of linear motion. |
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