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NEET Physics Semiconducting Devices NEET PYQ-Semiconducting Devices

  • question_answer
    In a common-base configuration of a transistor \[\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}=0.98\] then current gain in common emitter configuration of transistor will be:                                                              [AIPMT 2001]

    A)  49       

    B)                   98                   

    C)  4.9      

    D)                   24.5

    Correct Answer: A

    Solution :

    Key Idea: \[\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}\,\] is the current gain \[(\alpha )\] in common-base configuration.
                            \[\alpha =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}\,=\,0.98\]
                The current gain in common-emitter configuration
                            \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.98}{1-0.98}\]
                            \[=\frac{0.98}{0.02}=49\]


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