To get an output \[Y=1\] in given circuit which of the following input will be correct [AIPMT (M) 2012] |
A) 1 0 0
B) 1 0 1
C) 1 1 0
D) 0 1 0
Correct Answer: B
Solution :
Here \[Y=(A+B)\cdot C\] | ||||||||
Truth Table | ||||||||
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C should be 1 either A and B or both A and B are 1 | ||||||||
Therefore, \[A=1,B=0,C=1\] |
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