For the logic circuit shown, the truth table is: |
[NEET 2020] |
A) A B Y 0 0 0 0 1 1 1 0 1 1 1 1
B) A B Y 0 0 1 0 1 1 1 0 1 1 1 0
C) A B Y 0 0 1 0 1 0 1 0 0 1 1 0
D) A B Y 0 0 0 0 1 0 1 0 0 1 1 1
Correct Answer: D
Solution :
[d] | |||||||||||||||
\[\text{Y}\,\,\text{=}\,\,\overline{\overline{A}+\overline{B}}\] | |||||||||||||||
\[=\overline{\overline{A.B}}\] | |||||||||||||||
\[=A.B\Rightarrow AND\,\,Gate\] | |||||||||||||||
Truth Table | |||||||||||||||
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