A) 3 Hz
B) 2 Hz
C) 4 Hz
D) 1 Hz
Correct Answer: D
Solution :
| Maximum speed of a particle executing SHM is |
| \[{{u}_{\max }}=a\,\omega \,=a\,(2\pi n)\] |
| \[\Rightarrow \] \[n=\frac{{{u}_{\max }}}{2\pi a}\] |
| Here, \[{{u}_{\max }}\,=\text{ }31.4\text{ }cm/s,\text{ }a=5cm\] |
| Substituting, the given values, we have |
| \[n=\frac{31.4}{2\times 3.14\times 5}=1\,Hz\] |
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