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  • question_answer
    An organic compound containing C, H and N gave the following results on analysis C = 40%, H = 13.33%, N = 46.67%. Its empirical formula would be:                                [AIPMT 1998]

    A) \[{{C}_{2}}{{H}_{7}}{{N}_{2}}\]

    B) \[C{{H}_{5}}N\]

    C) \[C{{H}_{4}}N\]

    D) \[{{C}_{2}}{{H}_{7}}N\]

    Correct Answer: C

    Solution :

    [c] Table for empirical formula
    Element % At. Wt. Relative Number Ratio
    C 40.00 12 \[\frac{40}{12}=3.66\] \[\frac{3.66}{3.33}=1.09\tilde{\ }1\]
    H 13.33 1 \[\frac{13.33}{1}=13.33\] \[\frac{13.33}{3.33}=4\]
    N 46.67 14 \[\frac{46.67}{14}=3.33\] \[\frac{3.33}{3.33}=1\]
    Hence, empirical formula \[C{{H}_{4}}N\]


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