A) 0.549
B) 0.200
C) 0.786
D) 0.478
Correct Answer: D
Solution :
[d] Total vapour pressure of mixture |
= (Mole fraction of pentane V.P. of pentane) + (Mole fraction of hexane x V.P. of hexane) = V.P. of pentane in mixture + V.P. of hexane in mixture |
\[=\left( \frac{1}{5}\times 440+\frac{4}{5}\times 120 \right)=184\,mm\] |
\[\because \,\] V.P. of pentane in mixture |
= V.P. of mixture x mole fraction of pentane it vapour phase |
88 = 184 x mole fraction of pentane in vapour phase |
\[\therefore \] Mole fraction of pentane in vapour phase |
\[=\frac{88}{184}=0.478\] |
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