A) \[250\text{ }g\text{ }mo{{l}^{-1}}\]
B) \[300\text{ }g\text{ }mo{{l}^{-1}}\]
C) \[350\text{ }g\text{ }mo{{l}^{-1}}\]
D) \[200\text{ }g\text{ }mo{{l}^{-1}}\]
Correct Answer: B
Solution :
[b] 10 g per dm3 of urea is isotonic with 5% solution of a non-volatile solute. Hence, between these solution osmosis is not possible so their molar concentrations are equal to each other. |
Thus, molar concentration of urea solution |
\[=\frac{10\,g/d{{m}^{3}}}{Mol.\,wt.\,of\,urea}\] |
\[=\frac{10}{60}\,M=\frac{1}{6}\,M\] |
Molar concentration of 5% non-volatile solute |
\[=\frac{50\,g/d{{m}^{3}}}{mol.\,wt.\,of\,non-volatile\,solute}\] |
\[=\frac{50}{m}\,M\] |
Both solutions are isotonic to each other, therefore |
\[\frac{1}{6}=\frac{50}{m}\] |
\[orm=50\times 6=300\,g\,mo{{l}^{-1}}\] |
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