NEET Chemistry NEET PYQ-Solutions

  • question_answer
    A solution containing 10 g per \[d{{m}^{3}}\] of urea (molecular mass \[=60\text{ }g\text{ }mo{{l}^{-1}}\]) is isotonic with a 5% solution of a non-volatile solute. The molecular mass of this non-volatile solute is:                                        [AIPMT (S) 2006]

    A) \[250\text{ }g\text{ }mo{{l}^{-1}}\]

    B) \[300\text{ }g\text{ }mo{{l}^{-1}}\]        

    C) \[350\text{ }g\text{ }mo{{l}^{-1}}\]     

    D) \[200\text{ }g\text{ }mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

    [b] 10 g per dm3 of urea is isotonic with 5% solution of a non-volatile solute.  Hence, between these solution osmosis is not possible so their molar concentrations are equal to each other.
                Thus, molar concentration of urea solution
                \[=\frac{10\,g/d{{m}^{3}}}{Mol.\,wt.\,of\,urea}\]
                \[=\frac{10}{60}\,M=\frac{1}{6}\,M\]
                Molar concentration of 5% non-volatile solute
                \[=\frac{50\,g/d{{m}^{3}}}{mol.\,wt.\,of\,non-volatile\,solute}\]
                \[=\frac{50}{m}\,M\]
                Both solutions are isotonic to each other, therefore
                \[\frac{1}{6}=\frac{50}{m}\]
                \[orm=50\times 6=300\,g\,mo{{l}^{-1}}\]


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