A) 0.4 K
B) 0.3 K
C) 0.5 K
D) 0.2 K
Correct Answer: A
Solution :
| [a] Molality of non-electrolyte solute |
| \[=\frac{\frac{weight\,of\,solute\,in\,gram}{molecular\,weight\,of\,solute}}{weight\,of\,solvent\,in\,kg}\] |
| \[=\frac{\frac{1}{250}}{0.0512}=\frac{1}{250\times 0.0512}=0.0781\,m\] |
| \[\Delta {{T}_{f}}={{k}_{f}}\times molality\,of\,solution\] |
| \[=5.12\times 0.0781=0.4\,K\] |
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