A) 2
B) 3
C) 4
D) 1
Correct Answer: A
Solution :
| [a] Given, |
| molality,\[=[{{M}^{1}}{{L}^{1}}{{T}^{-2}}]\] |
| \[=[{{M}^{1}}{{L}^{1}}{{T}^{-2}}]\] |
| \[\therefore \] |
| \[\therefore \] |
| \[\text{ }\!\!\alpha\!\!\text{ -}\] |
| \[\text{ }\!\!\beta\!\!\text{ -}\] \[\text{ }\!\!\gamma\!\!\text{ -}\] |
| Since, the compound is ionic, so number of moles produced is equal to vant' Hoff factor, i. |
| Hence, 2 moles of ions are produced. |
| \[_{Z}^{A}X\xrightarrow[{}]{{}}{{\,}_{Z+}}_{1}^{A}Y+\beta _{-1}^{0}\] |
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