NEET Chemistry NEET PYQ-Solutions

  • question_answer
    200 mL of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be \[2.57\times {{10}^{-3}}\]bar. The molar mass of protein will be    (R = 0.083 L bar \[mo{{l}^{-1}}\])    [AIPMT (M) 2011]

    A) \[51022\text{ }g\text{ }mo{{l}^{-1}}\]

    B) \[122044\text{ }g\text{ }mo{{l}^{-1}}\]

    C) \[31011\text{ }g\text{ }mo{{l}^{-1}}\]

    D) \[61038\text{ }g\text{ }mo{{l}^{-1}}\]

    Correct Answer: D

    Solution :

    [d] \[\because \pi =CRT\]
    \[=\frac{w\times 1000}{M\times V(in\,mL)}\times RT\]
    \[\left[ \because \text{C}\,\text{=}\frac{\text{n}\,\text{ }\!\!\times\!\!\text{ 1000}}{\text{V(in}\,\text{mL)}}\text{and}\,\text{n}\,\text{=}\frac{\text{w}}{\text{M}} \right]\]
    \[\,\text{=}\frac{1.26\times 1000\times 0.083\times 300}{2.57\times {{10}^{-3}}\times 200}\]
    \[=61038\,g\,mo{{l}^{-1}}\]


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