NEET Chemistry NEET PYQ-Solutions

  • question_answer
    Which one of the following electrolytes has the same value of van't Hoffs factor (2) as that of \[A{{l}_{2}}{{\left( S{{O}_{4}} \right)}_{3}}\] (if all are 100% ionised)? [NEET 2015 ]

    A) \[{{K}_{2}}S{{O}_{4}}\]

    B) \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]

    C) \[Al{{(N{{O}_{3}})}_{3}}\]

    D) \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]

    Correct Answer: D

    Solution :

    [d] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}2A{{l}^{3+}}+3SO_{4}^{2-}\]
    Value of Van’t Hoff’s factor \[(i)=5\]
    \[{{K}_{2}}S{{O}_{4}}2{{K}^{+}}+SO_{4}^{2-}\]               \[(i=3)\]
    \[{{K}_{3}}[Fe{{(CN)}_{6}}]3{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{3-}}\]\[(i=4)\]
    \[Al{{(N{{O}_{3}})}_{3}}A{{l}^{3+}}+3NO_{3}^{-}\]         \[(i=4)\]
    \[{{K}_{4}}[Fe{{(CN)}_{6}}]4{{K}^{+}}+{{[Fe{{(CN)}_{6}}]}^{3-}}\]\[(i=5)\]
    Therefore, \[{{K}_{4}}[Fe{{(CN)}_{6}}]\] has same value of i that of \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]i.e. \[i=5\]


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