A) 27 u
B) 36 u
C) 64 u
D) 9 u
Correct Answer: B
Solution :
| From Graham's diffusion law, \[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] |
| or \[\frac{{{V}_{1}}}{{{t}_{1}}}\times \frac{{{t}_{2}}}{{{V}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] |
| \[\because \]Volume is same, |
| \[\therefore \]\[\frac{3}{1}=\sqrt{\frac{{{M}_{2}}}{4}}\]or\[9=\frac{{{M}_{2}}}{4}\]or\[{{M}_{2}}=9\times 4=36u\] |
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