A) 2.8
B) 4.0
C) 1.4
D) 2.0
Correct Answer: C
Solution :
| Average velocity \[=\sqrt{\frac{8RT}{\pi M}}\] |
| \[\therefore {{V}_{av}}\propto \sqrt{T}\]or\[\frac{{{({{V}_{av}})}_{2}}}{{{({{V}_{av}})}_{2}}}=\sqrt{\frac{2T}{T}}=1.4\] |
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