A) \[n=4,\,l=0,\,m=0,\,s=-1/2\]
B) \[n=5,\,l=3,\,m=0,\,s=+1/2\]
C) \[n=3,\,l=2,\,m=-3,\,s=-1/2\]
D) \[n=3,\,l=2,\,m=-2,\,s=-1/2\]
Correct Answer: C
Solution :
| Key Idea For an electron, n maybe 0, 1, 2 ... and \[l=0\] to \[n-1\] and \[m=-\,l\] to \[+\,l\] (including 0) |
| and \[s=\pm \,\frac{1}{2}\] |
| Hence; if \[n=3,\,l=0\] to \[(3-1)\] |
| = 0, 1, 2 |
| \[m=-\,l\] to \[+l\] |
| \[=-\,2,\,-1,\,0,\,+1,\,+2\] |
| \[s=\pm \,\frac{1}{2}\] |
| Therefore, option is not a permissible set of quantum numbers. |
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