question_answer

The de-Broglie wavelength of a particle with mass 1 g and velocity 100 m/s is:         [AIPMT 1999]

A)  \[6.63\times {{10}^{-33}}\,m\]

B)       \[6.63\times {{10}^{-34}}\,m\] C)  \[6.63\times {{10}^{-35}}\,m\] D)       \[6.65\times {{10}^{-36}}\,m\] Correct Answer: A Solution : \[p=\frac{h}{\lambda }\] (de-Broglie equation)

\[\lambda =\frac{h}{mv}\]         \[(\because \,\,p=mv)\]

\[\lambda =\frac{6.63\times {{10}^{-34}}\,kg\,{{m}^{2}}/s}{{{10}^{-3}}\,kg\times 100\,m/s}=6.63\times {{10}^{-33}}\,m\]