A) \[_{28}^{59}\text{Ni}\]
B) \[_{27}^{59}\text{Co}\]
C) \[_{28}^{60}\text{Ni}\]
D) \[_{27}^{60}\text{Co}\]
Correct Answer: C
Solution :
| [c] \[_{28}N{{i}^{60}}{{+}_{0}}{{n}^{1}}{{\xrightarrow[{}]{{}}}_{27}}C{{o}^{60}}+\underset{(p)}{\mathop{_{1}{{H}^{1}}}}\,\] |
| (\[n\], p means that neutron attacks and proton liberates) |
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