A) \[Cr>Mn>V>Ti\]
B) \[V>Mn>Cr>Ti\]
C) \[Mn>Cr>Ti>V\]
D) \[Ti>V>Cr>Mn\]
Correct Answer: D
Solution :
| [d] Key Idea: The amount of energy required to remove an electron from a unipositive ion is called second IP which generally increases in a period from left to right. |
| The second ionisation energies of the first transition series increase almost regularly with increase in atomic number. However, the value for Cr is sufficiently higher than those of its neighbour, ie, (Mn). This is due to stable configuration of \[C{{r}^{+}}\] (\[3{{d}^{5}}\] exactly half filled). |
| Note: The half-filled and completely filled configurations are more stable. |
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