A) 100 J
B) 99 J
C) 90 J
D) 1 J
Correct Answer: C
Solution :
| As, \[{{Q}_{1}}+W={{Q}_{2}}\] |
| Given, \[\eta =\frac{1}{10}\] |
| Now, using \[\eta =1-\frac{{{T}_{1}}}{{{T}_{2}}}\] |
| So, \[\frac{1}{10}=1-\frac{{{T}_{1}}}{{{T}_{2}}}\] |
| \[\Rightarrow \] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{9}{10}\] |
| Now \[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] |
| \[\Rightarrow \] \[\frac{{{Q}_{1}}}{{{Q}_{1}}+W}=\frac{9}{10}\] |
| \[\Rightarrow \] \[10{{Q}_{1}}\,=9{{Q}_{1}}\,+9W\] |
| \[\Rightarrow \] \[{{Q}_{1}}=9W=9\times 10=90J\] |
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