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NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी NEET PYQ-Thermodynamics

  • question_answer
    Enthalpy of \[C{{H}_{4}}+\frac{1}{2}{{O}_{2}}\to C{{H}_{3}}OH\] negative. If enthalpy of combustion of \[C{{H}_{4}}\] and \[C{{H}_{3}}OH\] are \[x\] and \[y\] respectively. Then which relation is correct?      [AIPMT 2001]

    A)  \[x>y\]

    B)                   \[x<y\]

    C)  \[x=y\]

    D)                   \[xy\]

    Correct Answer: A

    Solution :

    \[C{{H}_{4}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{H}_{3}}OH(l)\]
                \[\therefore \]\[\Delta H=-\,\,[(\Delta H\,\text{of}\,\text{combustion}\,\text{of}\,C{{H}_{3}}OH)\]
    \[-\,(\Delta H\,\text{of combustion of }C{{H}_{3}})]\]
    \[=-[(-y)-(-x)]\]
    \[=-[-y+x]=y-x\]
    \[\therefore \]      \[x>y\]


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