2. Solved Papers
  3. NEET
  4. Chemistry
  5. Thermodynamics / रासायनिक उष्मागतिकी

NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी NEET PYQ-Thermodynamics

  • question_answer
    On the basis of the information available from the reaction \[\frac{4}{3}Al+{{O}_{2}}\to \frac{2}{3}\,A{{l}_{2}}{{O}_{3}},\,\Delta G=-827\,kJ\,mo{{l}^{-1}}\] of \[{{O}_{2}},\] the minimum emf required to carry out an electrolysis of \[A{{I}_{2}}{{O}_{3}}\] is \[(F=96500\text{ }C\text{ }mo{{l}^{-1}})\]                                                                                             [AIPMT 2003]

    A)        6.42 V

    B)       8.56 V 

    C)  2.14 V 

    D)                   4.28 V

    Correct Answer: C

    Solution :

    \[\frac{4}{3}Al+{{O}_{2}}\to \frac{2}{3}A{{l}_{2}}{{O}_{3}},\Delta G=-827\,k\,J\,mo{{l}^{-1}}\]
                As we know that
                \[\because \]       \[\Delta G=-nEf\]            \[(value\,of\,n=4)\]
                            \[-827\times {{10}^{3}}\,J=-4\times E\times 96500\]
                            \[E=\frac{827\times {{10}^{3}}}{4\times 96500}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner