NEET Chemistry Thermodynamics / रासायनिक उष्मागतिकी NEET PYQ-Thermodynamics

  • question_answer
    Bond dissociation enthalpy of \[{{H}_{2}},C{{l}_{2}}\] and \[HCl\] are 434, 242 and 431 kJ \[mo{{l}^{-1}}\] respectively. Enthalpy of formation of HCl is                                                                                                                     [AIPMT (S) 2008]

    A)  \[93\,kJ\,mo{{l}^{-1}}\]          

    B)       \[-245\,kJ\,mo{{l}^{-1}}\]

    C)  \[-93\,kJ\,mo{{l}^{-1}}\]         

    D)       \[245\,kJ\,mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

    Key Idea:
    energy of reactant Bond energy of product
    Here,    
               
               


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