NEET Physics Thermometry, Calorimetry & Thermal Expansion NEET PYQ-Thermometry, Calorimetry and Thermal Expansion

  • question_answer
    When 1 kg of ice at \[0{{\,}^{o}}C\] melts to water at \[0{{\,}^{o}}C,\] the resulting change in its entropy, taking latent heat of ice to be \[80\text{ }cal/{}^\circ C,\] is                                                             [AIPMT (S) 2011]

    A)  \[8\times {{10}^{4}}\,cal/K\]

    B)       80 cal/K

    C)  293 cal/K   

    D)       273 cal/K

    Correct Answer: C

    Solution :

    Change in entropy \[\Delta S=\frac{ml}{T}=\frac{1000\times 80}{273}=293\,\,cal\,\,{{K}^{-1}}\]   

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