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NEET Physics Transmission of Heat NEET PYQ-Transmission Of Heat

  • question_answer
    The two ends of a metal rod are maintained at temperatures \[100{}^\circ C\] and \[110{}^\circ C\]. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures \[200{}^\circ C\] and \[210{}^\circ C,\] the rate of heat flow will be                                                                                                  [NEET  2015]

    A)  44.0 J/s                       

    B)  16.8 J/s

    C)  8.0 J/s                

    D)       4.0 J/s

    Correct Answer: D

    Solution :

    Here,     \[\Delta {{T}_{1}}=110-100={{10}^{o}}C\]
    \[\frac{d{{Q}_{1}}}{dt}=4J/s\]
    \[\Delta {{T}_{2}}=210-200={{10}^{o}}C\]
    \[\frac{d{{Q}_{2}}}{dt}=?\]
    As the rate of heat flow is directly proportional to the temperature difference and the temperature difference in both the cases is same i.e. \[10{}^\circ C\]. So, the same rate of heat will flow in the second case.
    Hence,  \[\frac{d{{Q}_{2}}}{dt}=4J/s\]


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