A) \[\theta ={{\tan }^{-1}}\left( \frac{1}{4} \right)\]
B) \[\theta ={{\tan }^{-1}}(4)\]
C) \[\theta ={{\tan }^{-1}}(2)\]
D) \[\theta ={{45}^{o}}\]
Correct Answer: B
Solution :
Given, \[R=H\] |
Range \[R=\frac{{{u}^{2}}(2\sin \theta \cos \theta )}{g}\] |
Height \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] |
Hence, \[\frac{{{u}^{2}}(2\sin \theta \cos \theta )}{g}=\frac{{{u}^{2}}{{\sin }^{2}}a}{2g}\] |
\[2\cos \theta =\frac{\sin \theta }{2}\] |
\[\tan \theta =4\] |
\[\theta ={{\tan }^{-1}}(4)\] |
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