A) 80 cm
B) 100 cm
C) 120 cm
D) 140 cm
Correct Answer: C
Solution :
The fundamental frequencies of closed and open organ pipe are given as |
\[{{v}_{c}}=\frac{v}{4l}\] |
\[{{v}_{o}}=\frac{v}{2l'}\] |
Given the second overtone (i.e., third harmonic) of open pipe is equal to the fundametal frequency of closed pipe |
i.e., \[3{{v}_{o}}={{v}_{c}}\] |
\[\Rightarrow \] \[3\frac{v}{2l'}=\frac{v}{4l}\] |
\[\Rightarrow \] \[1'=6l=6\times 20=120cm\] |
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