NEET Physics Wave Mechanics NEET PYQ-Wave Mechanics

  • question_answer
    The equation of a simple harmonic wave is given by\[y=3\sin \frac{\pi }{2}(50t-x),\] where x and y are in metres and t is in seconds. The ratio of maximum particle velocity to the wave velocity is                                 [AIPMT (M) 2012]

    A)  \[2\pi \]            

    B)       \[\frac{3}{2}\pi \]                     

    C)  \[3\pi \]            

    D)       \[\frac{2}{3}\pi \]

    Correct Answer: B

    Solution :

    We know that
    \[{{v}_{\max }}=a\omega \]
    and       \[v=n\lambda \]
    \[\therefore \]      \[\frac{{{v}_{\max }}}{v}=\frac{a\omega }{n\lambda }\]
                \[=\frac{a(2\pi n)}{n\pi }=\frac{2\pi a}{\lambda }\]
                \[=\frac{2\pi a}{2\pi /k}\]
                \[=ka=\frac{\pi }{2}\times 3\]
                \[=\frac{3\pi }{2}\]       


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