A) \[0.05{}^\circ \]
B) \[0.1{}^\circ \]
C) \[0.266{}^\circ \]
D) \[0.15{}^\circ \]
Correct Answer: D
Solution :
| [d] \[\theta \propto \lambda \] |
| \[{{\lambda }_{1}}=400\text{ }nm,{{\theta }_{1}}=0.2{}^\circ ,{{\mu }_{water}}=4/3\] |
| \[\frac{{{\theta }_{1}}}{{{\theta }_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\mu =\frac{c}{v}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{4}{3}\] |
| \[\frac{{{\theta }_{1}}}{{{\theta }_{2}}}=\frac{4}{3}\] |
| \[{{\theta }_{2}}=\frac{3}{4}({{\theta }_{1}})\] |
| \[=\frac{4}{3}(0.2{}^\circ )=0.15{}^\circ \] |
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