| A force F acting on an object varies with distance \[x\] as shown here. The force is in N and \[x\] is in m. The work done by the force in moving the object from \[x=0\] to \[x=6\,m\] is: [AIPMT (S) 2005] |
 |
A) 4.5 J
B) 13.5 J
C) 9.0 J
D) 18.0 J
Correct Answer: B
Solution :
| Key Idea: The work done will be the area of the \[F-x\] graph. |
| Work done in moving the object from \[x=0\] to \[x=6\,m\] is given by |
| \[W=\] area of rectangle + area of triangle |
| \[=3\times 3+\frac{1}{2}\times 3\times 3\] |
| \[=9+4.5\,=\,13.5\,J\] |
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