NEET Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति NEET PYQ-Work Energy Power and Collision

  • question_answer
    A ball is thrown vertically downwards from a height of 20 m with an initial velocity \[{{V}_{0}}\]. It collides with the ground, loses 50% of its energy in collision and rebounds to the same height. The initial velocity \[{{V}_{0}}\] is (Take,\[g=10m{{s}^{-2}}\])        [NEET 2015 (Re)]

    A) \[14\,\,m{{s}^{-1}}\]

    B) \[20\,\,m{{s}^{-1}}\]

    C) \[28\,\,m{{s}^{-1}}\]

    D) \[10\,\,m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    Suppose a ball rebounds with speed
                \[v=\sqrt{2gh}=\sqrt{2\times 10\times 20}=20m/s\]
    Energy of a ball just after rebound,
    \[E=\frac{1}{2}m{{v}^{2}}=200m\]
    As 50% of energy loses in collision means just before collision energy is 400 m.
    According to law of conservation of energy we have
                \[\frac{1}{2}mv_{0}^{2}+mgh=400m\]
    \[\Rightarrow \]   \[\frac{1}{2}mv_{0}^{2}+m\times 10\times 20=400m\]
    \[\Rightarrow \]   \[\,{{v}_{0}}=20m/s\]


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