A) 0.6
B) 0.06
C) 0.006
D) 6
Correct Answer: B
Solution :
| [b] \[1\text{ }eV=1.6\times {{10}^{19}}J\] |
| \[1\,J=\frac{1}{1.6\times {{10}^{-19}}}eV\] |
| \[{{10}^{-20}}J=\frac{{{10}^{-20}}}{1.6\times {{10}^{-19}}}eV\] |
| \[=0.06\,\,eV\] |
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