A) \[\frac{4}{3}\]
B) 2
C) \[\frac{5}{3}\]
D) \[\frac{3}{2}\]
Correct Answer: D
Solution :
According to question \[p\propto {{T}^{3}}\] \[pV=nRT\] And \[p\propto {{T}^{3}}\] \[\Rightarrow \] \[{{p}^{2}}{{V}^{3}}=\]constant \[p{{V}^{3/2}}=\]constant \[\because \] \[p{{V}^{\gamma }}=\]constant \[\therefore \] \[\gamma =\frac{3}{2}\]
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