A) 3 kg
B) 5 kg
C) 7kg
D) 17kg
Correct Answer: B
Solution :
We have \[{{p}_{1}}+{{p}_{2}}+{{p}_{3}}=0\] \[[\because P=mv]\] \[\therefore \] \[1\times 12i+2\times 8j+{{p}_{3}}=0\] \[\Rightarrow \]\[12i+16j+{{p}_{3}}=0\] \[\Rightarrow \]\[{{p}_{3}}=-(12i+16j)\] \[\therefore \]\[{{p}_{3}}=\sqrt{{{(12)}^{2}}+{{(16)}^{2}}}\] \[\sqrt{144+256}\] \[=20kg-m/s\] Now, \[{{p}_{3}}={{m}_{3}}{{v}_{3}}\] \[\Rightarrow \] \[{{m}_{3}}=\frac{{{p}_{3}}}{{{v}_{3}}}=\frac{20}{4}=5kg\]
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