NEET NEET SOLVED PAPER 2014

  • question_answer
    A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t = 0, (6m, 7m) at time t = 2 s and (13m, 14m) at time t = 5 s. Average velocity vector (\[{{\upsilon }_{a\upsilon }}\]) from t = 0 to t = 5 s is                   [AIPMT 2014]

    A)  \[\frac{1}{5}(13\mathbf{\hat{i}}+14\mathbf{\hat{j}})\]

    B)  \[\frac{7}{3}(\mathbf{\hat{i}}+\mathbf{\hat{j}})\]

    C)  \[2(\mathbf{\hat{i}}+\mathbf{\hat{j}}).\]

    D)  \[\frac{11}{5}(\mathbf{\hat{i}}+\mathbf{\hat{j}})\]

    Correct Answer: D

    Solution :

    Average velocity vector \[{{v}_{av}}=\frac{\text{Net}\,\text{displacement}}{\text{Time}\,\text{taken}}\] \[=\frac{(13-2)\hat{i}+(14-3)\hat{j}}{5}\] \[=\frac{11\text{\hat{i}+11\hat{j}}}{5}=\frac{11}{5}(\hat{i}+\text{\hat{j}})\]


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