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NEET NEET SOLVED PAPER 2014

  • question_answer
    When \[0.1\text{mol}\,\text{MnO}_{4}^{2-}\] is oxidised, the quantity of electricity required to completely oxidise \[MnO_{4}^{2-}\] is \[MnO_{4}^{-}\] [AIPMT 2014]

    A)  96500 C       

    B)  \[2\times 96500\,C\]

    C)  9650C          

    D)  96.50 C

    Correct Answer: C

    Solution :

    \[\underset{(+7)}{\mathop{MnO_{4}^{2-}}}\,\underset{(+6)}{\mathop{MnO_{4}^{-}}}\,\] As per the equation, for 1 mole of\[MnO_{4}^{2-}\], 1 F of electricity is required. Thus, for 0.1 mole of\[MnO_{4}^{2-}\], 0.1 F of electricity is required. Since,      1 F = 96500 C \[\therefore \]         \[0.1F=0.1\times 96500C\] = 9650 C Hence, 9650 C of electricity is required to completely oxidise \[MnO_{4}^{2-}\]to\[MnO_{4}^{-}\].


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