A) 37.33
B) 45.33
C) 35.33
D) 43.33
Correct Answer: A
Solution :
In Kjeldahl?s method, percentage of N is given by \[%N=\frac{\text{1}\text{.4 }\!\!\times\!\!\text{ Normality}\,\text{of}\,\text{acid }\!\!\times\!\!\text{ volume}\,\text{ofacid}}{\text{Weight}\,\text{of}\,\text{compound}}\] \[1M{{H}_{2}}S{{O}_{4}}=2N{{H}_{2}}S{{O}_{4}}\] \[\therefore \] \[%N=\frac{1.4\times 2\times 1}{0.75}=37.33%\]
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