A) Ethane
B) Ethyne
C) Ethene
D) Ethanol
Correct Answer: B
Solution :
Hybridisation of carbon = \[s{{p}^{3}}\]-number of \[s{{p}^{3-number\,\pi -bonds}}\] In \[C{{O}_{2}},(O\underset{1\pi }{\mathop{=}}\,C\underset{1\pi }{\mathop{=}}\,O)\] hybridisation of carbon = \[s{{p}^{3-2}}=sp\] In ethyne or acetylene, \[{{C}_{2}}{{H}_{2}},\,(H-C\overset{2\pi }{\mathop{\equiv \equiv }}\,\,C-H)\] hybridisation of carbon = \[s{{p}^{3-2}}=sp\]
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