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NEET NEET SOLVED PAPER 2015 (C)

  • question_answer
    The ratio of the specific heats \[\frac{{{C}_{p}}}{{{C}_{v}}}=\gamma \] in terms of degrees of freedom (n) is given by

    A)  \[\left( 1+\frac{1}{n} \right)\]   

    B)  \[\left( 1+\frac{n}{3} \right)\]   

    C)  \[\left( 1+\frac{2}{n} \right)\]   

    D)  \[\left( 1+\frac{2}{n} \right)\]

    Correct Answer: C

    Solution :

    The specific heat of gas at constant volume in terms of degree of freedom n is \[{{C}_{v}}=\frac{n}{2}R\] Also    \[{{C}_{p}}-{{C}_{v}}=R\] So        \[{{C}_{p}}=\frac{n}{2}R+R=R\left( 1+\frac{n}{2} \right)\] Now,       \[\gamma =\frac{{{C}_{p}}}{{{C}_{v}}}=\frac{R\left( 1+\frac{n}{2} \right)}{\frac{n}{2}R}=\frac{2}{n}+1\]


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