A) 44.0 J/s
B) 16.8 J/s
C) 8.0 J/s
D) 4.0 J/s
Correct Answer: D
Solution :
Here, \[\Delta {{T}_{1}}=110-100={{10}^{{}^\circ }}C\] \[\frac{d{{Q}_{1}}}{dt}=4J/s\] \[\Delta {{T}_{2}}=210-200={{10}^{{}^\circ }}C\] \[\frac{d{{Q}_{2}}}{dt}=?\] As the rate of heat flow is directly proportional to the temperature difference and the temperature difference in both the cases is same i.e. \[{{10}^{\text{o}}}C\]. So, the same rate of heat will flow in the second case. Hence, \[\frac{d{{Q}_{2}}}{dt}=4J/s\]You need to login to perform this action.
You will be redirected in
3 sec