question_answer

An ideal gas is compressed to half its initial volume by means of several process. Which of the process results in the maximum work done on the gas?                                                                           

A)  Adiabatic                           

B)  Isobaric              

C)         Isochoric            

D)         Isothermal

Correct Answer: C

Solution :

Given, ideal gas is compressed to half its initial volume i.e. \[{{V}_{0}}=\frac{V}{2}\] The isochoric process is one in which volume is kept constant, meaning that work done by the system will be zero i.e. \[{{W}_{isochoric}}=0\] As we know, work dine on the gas = Area under curve i.e. \[{{W}_{ediabatic}}>{{W}_{isothermal}}>{{W}_{isochoric}}\]