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NEET NEET SOLVED PAPER 2016 Phase-I

  • question_answer
    A refrigerator works between \[4{{\,}^{o}}C\] and \[30{{\,}^{o}}C.\] It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is: (Take 1 cal = 4.2 Joules)                                                                                                                                                                

    A)  2.365 W                              

    B)  23.65 W

    C)   236.5 W                             

    D)   2365 W

    Correct Answer: C

    Solution :

                     \[\beta =\frac{{{Q}_{2}}}{W}=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}\](Where \[{{Q}_{2}}\] is heat removed) \[\Rightarrow \]               \[\frac{600\times 4.2}{W}=\frac{277}{303-277}\] \[\Rightarrow \]               \[W=236.5\,\text{joule}\] \[\Rightarrow \]  \[Power\,\,=\,\,\frac{W}{t}=\frac{236.5\,joule}{1\,\sec }=236.5\,\,watt.\]


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