• # question_answer A refrigerator works between $4{{\,}^{o}}C$ and $30{{\,}^{o}}C.$ It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is: (Take 1 cal = 4.2 Joules)                                                                                                                                                                 A)  2.365 W                               B)  23.65 W C)   236.5 W                              D)   2365 W

$\beta =\frac{{{Q}_{2}}}{W}=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}$(Where ${{Q}_{2}}$ is heat removed) $\Rightarrow$               $\frac{600\times 4.2}{W}=\frac{277}{303-277}$ $\Rightarrow$               $W=236.5\,\text{joule}$ $\Rightarrow$  $Power\,\,=\,\,\frac{W}{t}=\frac{236.5\,joule}{1\,\sec }=236.5\,\,watt.$